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Punjab Board Class 11 Mathematics

Chapter 11: Trigonometric Functions and their Graphs — Class 11 Maths Notes

Trigonometric functions and their graphs: period, amplitude, domain and range with step-by-step sketches. This page has the theory, solved textbook examples, every exercise solution, MCQs and a formula sheet for Chapter 11.

Exercise solutions — Chapter 11

Every exercise of Trigonometric Functions and their Graphs solved step by step.

Mathematics 11 (Punjab Board)

Chapter 11: Trigonometric Functions and their Graphs — Theory

11.1 Trigonometric Functions of Real Numbers

Take the unit circle with centre at the origin. For any real number \(\theta\), let \(P(x, y)\) be the point on the unit circle reached by measuring an angle \(\theta\) in standard position from the positive \(x\)-axis. Then we define \(\cos \theta = x\) and \(\sin \theta = y\). Roman Urdu mein: yeh definition angle ko kisi point ki coordinates se jorti hai, isi liye \(\sin \theta\) aur \(\cos \theta\) har real \(\theta\) ke liye defined hain.

\[ \cos \theta = x\text{-coordinate of } P, \qquad \sin \theta = y\text{-coordinate of } P \]

Key point: The other four functions are defined from these two: \(\tan \theta = \dfrac{\sin \theta}{\cos \theta}\), \(\cot \theta = \dfrac{\cos \theta}{\sin \theta}\), \(\sec \theta = \dfrac{1}{\cos \theta}\), \(\csc \theta = \dfrac{1}{\sin \theta}\), each wherever its denominator is non-zero.

11.2 Domain and Range

Since every point \(P\) on the unit circle has coordinates between \(-1\) and \(1\), sine and cosine accept every real number but only produce values in \([-1, 1]\).

\[ \text{Domain of } \sin, \cos = \mathbb{R}, \qquad \text{Range of } \sin, \cos = [-1, 1] \]

\(\tan \theta\) is undefined where \(\cos \theta = 0\), i.e. at \(\theta = \pm\frac{\pi}{2}, \pm\frac{3\pi}{2}, \dots\); its range is all of \(\mathbb{R}\). \(\sec \theta\) shares the domain of \(\tan \theta\), while \(\csc \theta\) and \(\cot \theta\) are undefined where \(\sin \theta = 0\), i.e. at \(\theta = 0, \pm\pi, \pm 2\pi, \dots\)

Key point: For exams, remember the restricted values: \(-1 \le \sin \theta \le 1\) and \(-1 \le \cos \theta \le 1\) — most max/min questions of this chapter start exactly here.

11.3 Even and Odd Functions

A function \(f\) is even if \(f(-x) = f(x)\) for every \(x\) in its domain; its graph is symmetric about the \(y\)-axis. It is odd if \(f(-x) = -f(x)\); its graph is symmetric about the origin. Agar dono mein se koi condition poori na ho, to function neither even nor odd hota hai.

\[ \cos(-x) = \cos x \;\; (\text{even}), \qquad \sin(-x) = -\sin x \;\; (\text{odd}), \qquad \tan(-x) = -\tan x \;\; (\text{odd}) \]

Quick rules: an even power of an odd function is even (for example \(\sin^2 x\)); a sum of an even and an odd function is generally neither.

Key point: Always test with \(f(-x)\) and compare with both \(f(x)\) and \(-f(x)\) — checking only one side is the most common error.

11.4 Periodic Functions

A function is periodic if its values repeat after a fixed interval; the smallest such positive interval is the period. Sine and cosine repeat every \(2\pi\) radians, while tangent and cotangent repeat every \(\pi\) radians.

\[ \text{Period of } \sin bx, \cos bx, \sec bx, \csc bx = \frac{2\pi}{|b|}, \qquad \text{Period of } \tan bx, \cot bx = \frac{\pi}{|b|} \]

Vertical shifts (adding a constant \(d\)) and phase shifts (replacing \(x\) by \(x + c\)) do not change the period — sirf \(x\) ke saath multiply hone wala number \(b\) period ko affect karta hai.

Key point: In \(y = a\sin(bx + c) + d\), read the period from \(b\) alone; \(a\), \(c\) and \(d\) are irrelevant to it.

11.5 Graphs of the Sine, Cosine and Tangent Functions

The sine curve starts at the origin, rises to \(1\) at \(\frac{\pi}{2}\), returns to \(0\) at \(\pi\), falls to \(-1\) at \(\frac{3\pi}{2}\) and completes one full wave at \(2\pi\). The cosine curve is the same wave shifted left by \(\frac{\pi}{2}\): it starts at its maximum \((0, 1)\). Tangent has period \(\pi\), passes through the origin, and has vertical asymptotes where cosine is zero.

\[ \sin x = 0 \text{ at } x = n\pi, \qquad \cos x = 0 \text{ at } x = \frac{\pi}{2} + n\pi, \qquad \tan x \text{ has asymptotes at } x = \frac{\pi}{2} + n\pi \]

Key point: To sketch any of these on paper, first write down the period and the quarter-points \(0, \frac{T}{4}, \frac{T}{2}, \frac{3T}{4}, T\) — the graph is then fixed.

11.6 Amplitude, Period and Phase Shift of \(y = a\sin(bx + c) + d\)

For a sinusoidal function written in the standard form \(y = a\sin(bx + c) + d\) (the same applies with cosine):

\[ \text{Amplitude } = |a|, \qquad \text{Period } T = \frac{2\pi}{|b|}, \qquad \text{Phase shift } = -\frac{c}{b}, \qquad \text{Vertical shift (midline) } = d \]

The graph oscillates between \(d - |a|\) and \(d + |a|\); \(d\) is the average or midline of the oscillation. Frequency (cycles per unit \(x\)) equals \(\dfrac{1}{T} = \dfrac{|b|}{2\pi}\). Negative \(a\) simply flips the wave upside down — start at the minimum instead of the maximum.

Key point: Amplitude is always a positive number \(|a|\); students often forget the modulus sign when \(a\) is negative.

11.7 Maximum and Minimum Values

Because \(-1 \le \sin u \le 1\) and \(-1 \le \cos u \le 1\) for every \(u\), the function \(f(x) = a + b\sin u\) attains its largest value when \(\sin u\) has the same sign as \(b\) and its smallest value in the opposite case. Yahi principle har max/min sawal ki buniyad hai.

\[ \max(a + b\sin u) = a + |b|, \qquad \min(a + b\sin u) = a - |b| \]

For a reciprocal such as \(\dfrac{1}{a + b\sin u}\) (with \(a + b\sin u > 0\) throughout), the maximum occurs where the denominator is smallest and the minimum where the denominator is largest — reciprocal max aur min ko ulat deta hai.

Key point: Before taking a reciprocal, confirm the denominator never reaches zero or changes sign on the interval in question.

11.8 Applications: Modelling Periodic Phenomena

Anything that repeats in time — temperature over a day, a Ferris wheel, tides, a swing — can be modelled by \(y = a\sin(bx + c) + d\). The modelling steps are: (1) amplitude \(|a|\) = half the total swing (radius for a wheel); (2) midline \(d\) = average value (centre height of the wheel); (3) \(b = \dfrac{2\pi}{T}\) from the observed period \(T\); (4) choose sine or cosine and the sign so that the model starts at the correct point (use \(-\cos\) if it starts at the lowest point).

\[ h(t) = -r\cos\left(\frac{2\pi}{T}t\right) + h_{\text{centre}} \quad \text{(wheel starting at the bottom)} \]

Angle-of-elevation/depression problems are solved by drawing the right triangles, writing \(\tan(\text{angle}) = \dfrac{\text{height}}{\text{base}}\) for each, and solving the resulting equations — this is the standard "two ships / two observers" pattern of Exercise 11.3.

Key point: In elevation/depression problems always label the unknown height and the unknown horizontal distances first; the two tangent equations then solve themselves.

Mathematics 11 (Punjab Board)

Solved Examples — Chapter 11: Trigonometric Functions and their Graphs

Worked solutions for Punjab Board Class 11 Mathematics, Chapter 11: Trigonometric Functions and their Graphs.

Example 2: Find the periods of: (i) \(\sin 2x\) (ii) \(3 + \tan \frac{x}{3}\)

Period nikalne ke liye hum \(\sin bx\) ka period \(\frac{2\pi}{|b|}\) aur \(\tan bx\) ka period \(\frac{\pi}{|b|}\) use karenge. Constant terms (jaise \(+3\)) period ko change nahi karte.

(i) The period of \(\sin\) is \(2\pi\), so \(\sin(2x + 2\pi) = \sin 2x\).

\[ \sin(2x + 2\pi) = \sin\bigl(2(x + \pi)\bigr) \]

Thus the values of \(\sin 2x\) repeat when \(x\) increases by \(\pi\).

(ii) For \(\tan \frac{x}{3}\), only the tangent part matters for the period. The period of \(\tan\) is \(\pi\):

\[ \tan\left(\frac{x}{3} + \pi\right) = \tan\frac{x}{3} \implies \tan\left(\frac{1}{3}(x + 3\pi)\right) = \tan\frac{x}{3} \]

So \(\tan \frac{x}{3}\) repeats when \(x\) increases by \(3\pi\), and adding the constant \(3\) does not affect the period.

Answer: (i) \(\pi\), (ii) \(3\pi\)

Example 4: Find the maximum and minimum values of: (i) \(2 + 3\sin x\) (ii) \(5 - 2\cos 3x\) (iii) reciprocal of (ii)

Hum \(-1 \le \sin u, \cos u \le 1\) ka use karenge: expression ki maximum value ke liye \(\sin u\) (ya \(\cos u\)) ko \(\pm 1\) mein se woh value dein jo coefficient ke sign ke saath maximum banaye.

(i) Let \(f(x) = 2 + 3\sin x\). Since \(-1 \le \sin x \le 1\):

\[ \max f = 2 + 3(1) = 5 \quad (\text{when } \sin x = 1), \qquad \min f = 2 + 3(-1) = -1 \quad (\text{when } \sin x = -1) \]

(ii) Let \(f(x) = 5 - 2\cos 3x\). Write it as \(5 + (-2)\cos 3x\); maximum occurs when \(\cos 3x = -1\):

\[ \max f = 5 - 2(-1) = 7, \qquad \min f = 5 - 2(1) = 3 \]

(iii) Let \(g(x) = \dfrac{1}{5 - 2\cos 3x}\). From (ii), the denominator lies between \(3\) and \(7\) (always positive). The reciprocal is largest when the denominator is smallest:

\[ \max g = \frac{1}{3}, \qquad \min g = \frac{1}{7} \]
Answer: (i) max \(5\), min \(-1\); (ii) max \(7\), min \(3\); (iii) max \(\frac{1}{3}\), min \(\frac{1}{7}\)

Example 6: A Ferris wheel with a radius of 45 feet has its lowest point located 5 feet above the ground. It completes one full revolution every 60 seconds in counter clock wise direction. Model an equation that describes the height of a rider on the Ferris wheel as a function of time \(t\). How high is the rider from the ground after 40 seconds? Also graph the model equation.

Rider sab se neeche se start karta hai, is liye hum \(-\cos\) wala model use karenge: amplitude = radius, midline = centre ki height, aur \(c = \frac{2\pi}{\text{period}}\).

Period \(T = 60\) s, so the angular frequency is

\[ \frac{2\pi}{c} = 60 \implies c = \frac{2\pi}{60} = \frac{\pi}{30} \]

Amplitude \(b =\) radius \(= 45\) ft. The centre of the wheel is \(5 + 45 = 50\) ft above the ground, so the vertical shift is \(a = 50\). Starting at the lowest point, use the negative cosine model:

\[ h(t) = -45\cos\left(\frac{\pi}{30}t\right) + 50 \]

After \(40\) seconds:

\[ h(40) = -45\cos\left(\frac{\pi}{30} \cdot 40\right) + 50 = -45\cos\left(\frac{4\pi}{3}\right) + 50 \]
\[ = -45\left(-\frac{1}{2}\right) + 50 = 22.5 + 50 = 72.5 \]

To graph it, plot \(h(t)\) for one period \(0 \le t \le 60\): it starts at \(5\) ft, rises to \(95\) ft at \(t = 30\) s, and returns to \(5\) ft at \(t = 60\) s.

Answer: \(h(t) = -45\cos\left(\frac{\pi t}{30}\right) + 50\); height after 40 s \(= 72.5\) feet

Example 8: The water level \(L\) (in feet) of a tidal river varies throughout the day according to \(L(t) = 8 + 4\sin\left(\frac{\pi}{6}t\right)\), where \(t\) is the time in hours. (a) Find the water level at \(t = 3\) hours. (b) What is the minimum water level?

(a) mein \(t = 3\) ki value equation mein rakh kar simplify karenge; (b) mein sine ki minimum value \(-1\) use karenge.

(a) Substitute \(t = 3\):

\[ L(3) = 8 + 4\sin\left(\frac{\pi}{6} \cdot 3\right) = 8 + 4\sin\left(\frac{\pi}{2}\right) = 8 + 4(1) = 12 \]

(b) The minimum of \(\sin\) is \(-1\):

\[ L_{\min} = 8 + 4(-1) = 4 \]
Answer: (a) \(12\) feet, (b) minimum water level \(= 4\) feet

Example 10: From a point 100 m above the surface of a lake, the angle of elevation of a peak of a cliff is \(15^\circ\) and the angle of depression of the image of the peak is \(30^\circ\). Find the height of the peak.

Do right triangles banayenge: ek peak ki taraf (elevation \(15^\circ\)), doosra lake mein bane image ki taraf (depression \(30^\circ\)). Dono mein \(\tan = \frac{\text{opposite}}{\text{adjacent}}\) likh kar equations solve karenge.

Let \(A\) be the top of the peak and \(AM = h\) metres its height. Let \(P\) be the point of observation, \(100\) m above the lake surface. Draw \(PQ\) horizontal to meet \(AM\) at \(Q\). Then \(QM = 100\) m, so \(AQ = h - 100\). The image \(B\) of the peak lies \(h\) m below the surface, so \(BQ = 100 + h\). Let \(PQ = y\).

\[ \tan 15^\circ = \frac{AQ}{PQ} = \frac{h - 100}{y}, \qquad \tan 30^\circ = \frac{BQ}{PQ} = \frac{h + 100}{y} \]

Dividing the two equations to eliminate \(y\):

\[ \frac{\tan 15^\circ}{\tan 30^\circ} = \frac{h - 100}{h + 100} \]

Apply componendo and dividendo:

\[ \frac{\tan 15^\circ + \tan 30^\circ}{\tan 15^\circ - \tan 30^\circ} = \frac{2h}{-200} = -\frac{h}{100} \]
\[ h = 100 \cdot \frac{\tan 30^\circ + \tan 15^\circ}{\tan 30^\circ - \tan 15^\circ} = 100 \cdot \frac{0.5774 + 0.2679}{0.5774 - 0.2679} \approx 100 \cdot \frac{0.8453}{0.3094} \approx 273.2 \]
Answer: height of the peak \(\approx 273.2\) m

Mathematics 11 (Punjab Board)

MCQs: Chapter 11 – Trigonometric Functions and their Graphs

  1. The domain of the sine function is

    1. \([-1, 1]\)
    2. \(\mathbb{R}\) (all real numbers)
    3. \([0, 2\pi]\)
    4. \(\mathbb{R} - \{n\pi\}\)
    \(\sin \theta\) har real angle ke liye defined hai (unit circle par har \(\theta\) ek point deta hai), jabke \([-1,1]\) uski range hai.
  2. The range of \(f(x) = \cos x\) is

    1. \(\mathbb{R}\)
    2. \((-\infty, \infty)\)
    3. \([-1, 1]\)
    4. \([0, 1]\)
    Unit circle par \(x\)-coordinate kabhi \(-1\) se kam ya \(1\) se zyada nahi hoti, is liye range \([-1,1]\) hai.
  3. \(\sin(-x)\) equals

    1. \(-\sin x\)
    2. \(\sin x\)
    3. \(\cos x\)
    4. \(-\cos x\)
    Sine ek odd function hai: \(f(-x) = -f(x)\), is liye \(\sin(-x) = -\sin x\).
  4. Which of the following functions is even?

    1. \(\sin x\)
    2. \(\tan x\)
    3. \(\sin x + \cos x\)
    4. \(\cos x\)
    \(\cos(-x) = \cos x\) hone ki wajah se cosine even hai; \(\sin x\) aur \(\tan x\) odd hain, aur \(\sin x + \cos x\) neither hai.
  5. \(f(x) = \sin^2 x\) is

    1. odd
    2. even
    3. neither even nor odd
    4. both even and odd
    \(f(-x) = \sin^2(-x) = (-\sin x)^2 = \sin^2 x = f(x)\), is liye even.
  6. The period of \(\sin 4x\) is

    1. \(\frac{\pi}{2}\)
    2. \(\frac{2\pi}{4} = 2\pi\)
    3. \(4\pi\)
    4. \(\pi\)
    \(\sin bx\) ka period \(\frac{2\pi}{|b|}\); yahan \(b = 4\), to period \(= \frac{2\pi}{4} = \frac{\pi}{2}\).
  7. The period of \(\tan 3x\) is

    1. \(\frac{2\pi}{3}\)
    2. \(3\pi\)
    3. \(\frac{\pi}{3}\)
    4. \(\frac{\pi}{6}\)
    Tangent ka period \(\frac{\pi}{|b|}\) hota hai (sine jaisa \(2\pi\) nahi), is liye \(\frac{\pi}{3}\).
  8. The period of \(\cot \frac{x}{2}\) is

    1. \(\pi\)
    2. \(\frac{\pi}{2}\)
    3. \(4\pi\)
    4. \(2\pi\)
    \(\cot bx\) ka period \(\frac{\pi}{|b|}\); \(b = \frac{1}{2}\) hone se period \(= \frac{\pi}{1/2} = 2\pi\).
  9. The period of \(19\sin\left(\frac{\pi}{20}x\right)\) is

    1. \(20\)
    2. \(40\)
    3. \(\frac{2\pi}{19}\)
    4. \(19\)
    \(b = \frac{\pi}{20}\), to period \(= \frac{2\pi}{\pi/20} = 40\); constant \(19\) period par asar nahi karta.
  10. The period of \(6 - 4\cot\left(\frac{7x}{4} + \frac{\pi}{4}\right)\) is

    1. \(\frac{2\pi}{7}\)
    2. \(\frac{7\pi}{4}\)
    3. \(\frac{4\pi}{7}\)
    4. \(\frac{\pi}{7}\)
    \(\cot\) ka period \(\frac{\pi}{|b|}\) with \(b = \frac{7}{4}\): \(\frac{\pi}{7/4} = \frac{4\pi}{7}\); phase shift \(\frac{\pi}{4}\) irrelevant hai.
  11. For \(y = 2 + 3\sin x\), the amplitude is

    1. \(3\)
    2. \(2\)
    3. \(5\)
    4. \(1\)
    Standard form \(a + b\sin(\cdot)\) mein amplitude \(= |b| = 3\); \(2\) to vertical shift hai.
  12. The maximum value of \(3 - \sin 3x\) is

    1. \(2\)
    2. \(3\)
    3. \(-1\)
    4. \(4\)
    Maximum ke liye \(\sin 3x = -1\) rakhein: \(3 - (-1) = 4\). Minus sign bhoolna sab se aam ghalti hai.
  13. The minimum value of \(1 - 3\cos 2x\) is

    1. \(4\)
    2. \(-4\)
    3. \(-2\)
    4. \(-3\)
    Minimum ke liye \(\cos 2x = 1\): \(1 - 3(1) = -2\).
  14. The maximum value of \(\dfrac{1}{10 - 2\sin 3x}\) is

    1. \(\frac{1}{12}\)
    2. \(\frac{1}{8}\)
    3. \(\frac{1}{10}\)
    4. \(8\)
    Denominator \(8\) se \(12\) tak hai (positive); fraction sab se bara jab denominator sab se chhota: \(\frac{1}{8}\).
  15. \(\tan x\) is undefined at

    1. \(x = n\pi\)
    2. \(x = \frac{\pi}{2} + n\pi\)
    3. \(x = 2n\pi\)
    4. \(x = \frac{\pi}{4} + n\pi\)
    \(\tan x = \frac{\sin x}{\cos x}\); jahan \(\cos x = 0\) (i.e. \(\frac{\pi}{2} + n\pi\)), wahan tangent undefined aur asymptote hota hai.
  16. The graph of \(y = \sin x\) passes through the origin and first reaches its maximum at

    1. \(x = \pi\)
    2. \(x = 2\pi\)
    3. \(x = \frac{\pi}{4}\)
    4. \(x = \frac{\pi}{2}\)
    Sine \(0\) se start karke \(\frac{\pi}{2}\) par \(1\) tak pahunchta hai, phir \(\pi\) par wapas \(0\) hota hai.
  17. For \(y = -30\cos\left(\frac{\pi}{40}t\right) + 36\), the midline (vertical shift) is

    1. \(30\)
    2. \(36\)
    3. \(66\)
    4. \(6\)
    \(y = a\cos(\cdot) + d\) mein \(d = 36\) midline hai (Ferris wheel ke centre ki height); \(30\) amplitude hai.
  18. The function \(f(x) = \dfrac{\sin x + \sin 3x}{\cos x + \cos 3x}\) is

    1. even
    2. neither
    3. odd
    4. constant
    \(f(-x) = \frac{-\sin x - \sin 3x}{\cos x + \cos 3x} = -f(x)\), is liye odd.
  19. If \(\sin x = \cos x\) for \(x \in [0, \pi]\), then \(x =\)

    1. \(\frac{\pi}{2}\)
    2. \(\frac{3\pi}{4}\)
    3. \(0\)
    4. \(\frac{\pi}{4}\)
    Dono sides ko \(\cos x\) se divide karein: \(\tan x = 1\), aur \([0,\pi]\) mein yeh \(x = \frac{\pi}{4}\) par hota hai.
  20. The number of solutions of \(\sin x = x\) in \([0, \pi]\) is

    1. \(0\)
    2. \(2\)
    3. \(1\)
    4. infinitely many
    \(x > 0\) ke liye \(\sin x < x\) hota hai, is liye graphs sirf origin par milte hain — ek hi solution \(x = 0\).
  21. The vertical asymptotes of \(y = \tan 2x\) in \((-\pi, \pi)\) include \(x =\)

    1. \(0\)
    2. \(\pm\frac{\pi}{4}\)
    3. \(\pm\frac{\pi}{2}\)
    4. \(\pm\pi\)
    Asymptotes jahan \(\cos 2x = 0\): \(2x = \pm\frac{\pi}{2}, \pm\frac{3\pi}{2}\), yani \(x = \pm\frac{\pi}{4}, \pm\frac{3\pi}{4}\).
  22. The graph of \(y = \sin 2x\) completes how many full waves on \([0, 2\pi]\)?

    1. \(1\)
    2. \(4\)
    3. \(2\)
    4. \(\frac{1}{2}\)
    Period \(= \frac{2\pi}{2} = \pi\); interval \(2\pi\) mein \(\frac{2\pi}{\pi} = 2\) complete waves aati hain.
  23. \(f(x) = \frac{1}{\sec x + \cot^2 x}\) is

    1. odd
    2. neither
    3. even
    4. not a function
    \(\sec(-x) = \sec x\) aur \(\cot^2(-x) = (-\cot x)^2 = \cot^2 x\), is liye \(f(-x) = f(x)\) — even.

Mathematics 11 (Punjab Board)

Chapter 11: Trigonometric Functions and their Graphs — Formula Sheet

Definitions on the Unit Circle

\[ \cos \theta = x, \quad \sin \theta = y \]
\[ \tan \theta = \frac{\sin \theta}{\cos \theta}, \quad \cot \theta = \frac{\cos \theta}{\sin \theta}, \quad \sec \theta = \frac{1}{\cos \theta}, \quad \csc \theta = \frac{1}{\sin \theta} \]

Domain and Range

\[ \text{Domain}(\sin) = \text{Domain}(\cos) = \mathbb{R}, \quad \text{Range}(\sin) = \text{Range}(\cos) = [-1, 1] \]
\[ -1 \le \sin \theta \le 1, \qquad -1 \le \cos \theta \le 1 \]
\[ \tan \theta \text{ undefined at } \theta = \frac{\pi}{2} + n\pi, \quad \cot \theta \text{ undefined at } \theta = n\pi \]

Even and Odd Tests

\[ f \text{ even } \iff f(-x) = f(x), \qquad f \text{ odd } \iff f(-x) = -f(x) \]
\[ \cos(-x) = \cos x, \quad \sin(-x) = -\sin x, \quad \tan(-x) = -\tan x \]
\[ \sec(-x) = \sec x, \quad \csc(-x) = -\csc x, \quad \cot(-x) = -\cot x \]

Periods

\[ \text{Period of } \sin bx,\ \cos bx,\ \sec bx,\ \csc bx = \frac{2\pi}{|b|} \]
\[ \text{Period of } \tan bx,\ \cot bx = \frac{\pi}{|b|} \]

Standard Sinusoidal Form \(y = a\sin(bx + c) + d\)

\[ \text{Amplitude} = |a|, \qquad \text{Period} = \frac{2\pi}{|b|} \]
\[ \text{Phase shift} = -\frac{c}{b}, \qquad \text{Vertical shift (midline)} = d \]
\[ \text{Frequency} = \frac{1}{T} = \frac{|b|}{2\pi} \]

Maximum and Minimum Values

\[ \max(a + b\sin u) = a + |b|, \qquad \min(a + b\sin u) = a - |b| \]
\[ \max(a + b\cos u) = a + |b|, \qquad \min(a + b\cos u) = a - |b| \]

Modelling a Ferris Wheel (starting at the lowest point)

\[ h(t) = -r\cos\left(\frac{2\pi}{T}t\right) + h_{\text{centre}} \]
\[ \tan(\text{angle of elevation/depression}) = \frac{\text{height}}{\text{horizontal distance}} \]

Chapter 11 FAQs

What is covered in Chapter 11 (Trigonometric Functions and their Graphs)?
This chapter covers Domain, range, period, amplitude, graphs of sine, cosine, tangent. The page includes theory and definitions, solved textbook examples, complete exercise solutions, MCQs and a formula sheet.
How many marks does Chapter 11 carry in the Punjab Board paper?
Chapter 11 (Trigonometric Functions and their Graphs) carries approximately 3 marks in the Punjab Board Class 11 Mathematics paper.
Are these notes for the new PCTB syllabus?
Yes. These notes follow the PCTB 2025 new book for Class 11 Mathematics, used by BISE Lahore, Gujranwala, Rawalpindi, Faisalabad, Multan, Sahiwal, Sargodha, Bahawalpur and D.G. Khan.
Where are the exercise solutions for Chapter 11?
Use the exercise index on this page — every exercise of Chapter 11 has its own page with complete step-by-step solutions.